0=-16t^2+82.7t

Solution for 0=-16t^2+82.7t equation:

0=-16t^2+82.7t

We move all terms to the left:

0-(-16t^2+82.7t)=0

We add all the numbers together, and all the variables

-(-16t^2+82.7t)=0

We get rid of parentheses

16t^2-82.7t=0

a = 16; b = -82.7; c = 0;
Δ = b2-4ac
Δ = -82.72-4·16·0
Δ = 6839.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-82.7)-\sqrt{6839.29}}{2*16}=\frac{82.7-\sqrt{6839.29}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-82.7)+\sqrt{6839.29}}{2*16}=\frac{82.7+\sqrt{6839.29}}{32}
$